-8x^2-64x-96=0

Solution for -8x^2-64x-96=0 equation:

-8x^2-64x-96=0

a = -8; b = -64; c = -96;
Δ = b2-4ac
Δ = -642-4·(-8)·(-96)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-32}{2*-8}=\frac{32}{-16}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+32}{2*-8}=\frac{96}{-16}
=-6
$